CBSE Class 10 Mathematics Standard 2025: question 31
Set in the CBSE Class 10 board exam of 2025, paper 30/3/1, section C, question 31, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q31 · 3 marks · Short answerCircles
In the given figure, PC is a tangent to the circle at C. AOB is the diameter which when extended meets the tangent at P. Find CBA and BCO, if PCA .
Figure in the paper: A circle with centre O. Diameter AOB lies horizontally, with B on the left and A on the right; O between them. The line AB extended beyond B meets the tangent at P on the far left. PC is the tangent touching the circle at C (top). Chords/segments CA, CB and radius CO are drawn. PCA is marked at C. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/3/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
AB is a diameter. What is the angle ACB?
Hint 2
Split to find . Then use the fact that OC ⟂ PC, and that OB = OC.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
[angle in a semicircle, since AB is a diameter]
- 1 mark
, so .
Hence .
- 1 mark
[tangent ⟂ radius at the point of contact].
So .
- ½ mark
OB = OC [radii], so [angles opposite equal sides].
Hence .
Answer: ,
Where the marks are
- (angle in semicircle) (½ mark)
- (1 mark)
- using tangent ⟂ radius (1 mark)
- using OB = OC (½ mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
- Topic: Tangent Perpendicular to Radius Theorem
More questions from Circles
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.