CBSE Class 10 Mathematics Standard 2025: question 26(a)
Set in the CBSE Class 10 board exam of 2025, paper 30/1/1, section C, question 26(a), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q26(a) · 3 marks · Short answerCircles
In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that .
Figure in the paper: Circle with centre O. Line BCD is tangent at C (B left, D right). Line from B passes through P (on circle) and O to A on the circle. OC (dashed) and AC are joined. Angle BAC is marked at A. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
OA and OC are both radii. What does that tell you about ?
Hint 2
Radius OC meets the tangent BD at . Split into two parts and substitute.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
In , (radii of the same circle). Therefore [angles opposite equal sides].
- 1 mark
[tangent ⟂ radius at the point of contact], so .
- ½ mark
, so .
- ½ mark
Using : . Since O lies on AB, . Hence . Proved.
Answer: (proved)
Where the marks are
- Uses OA = OC to get (1 mark)
- States (tangent ⟂ radius) (1 mark)
- Writes (½ mark)
- Substitutes to conclude (½ mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
- Topic: Tangent Perpendicular to Radius Theorem
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.