CBSE Class 10 Mathematics Standard sample paper 2025-26: question 29(B)
From the official CBSE sample question paper for 2025-26, section C, question 29(B), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q29(B) · 3 marks · Short answerIntroduction to Trigonometry
Prove that
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
Look for a factor that turns the denominator into a difference of squares.
Hint 2
Multiply above and below by .
Hint 3
Replace by and take out the common factor.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Multiply the numerator and the denominator by :
LHS . - 1 mark
[using in the denominator].
- 1 mark
In the numerator, , so it becomes .
LHS = RHS. Hence proved.
Answer: LHS = cosec A + cot A (proved)
Where the marks are
- Multiplies the numerator and denominator by (1 mark)
- Simplifies to (1 mark)
- Reduces this to (1 mark)
Revise the chapter
- Chapter: Introduction to Trigonometry (notes, formulas, where marks are lost and every past question)
- Topic: Proving Simple Trigonometric Identities
More questions from Introduction to Trigonometry
- 2025 board paper, set 30/1/1 (Standard), Q5 · 1 markThe value of ²θ - ((1)/(θ) × θ ) is :
- 2025 board paper, set 30/1/1 (Standard), Q27(a) · 3 marksProve that : (θ)/(1 - θ) + (θ)/(1 - θ) = 1 + θ cosec θ
- 2025 board paper, set 30/1/1 (Standard), Q27(b) · 3 marksProve that : ( A + A)/( A - A) + ( A - A)/( A + A) = (2)/(2² A - 1)
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