MathsCBSE Class 10 · Standard · Sample paper, session 2025-26 · 2 marks · Very short answer

CBSE Class 10 Mathematics Standard sample paper 2025-26: question 21(B)

From the official CBSE sample question paper for 2025-26, section B, question 21(B), for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q21(B) · 2 marks · Very short answerArithmetic Progressions

Find the middle term of A.P 6,13, 20, ……., 230

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.

Hints

Open one hint at a time and try again before the next.

Hint 1

First find how many terms the A.P. has.

Hint 2

With an odd number of terms n, the middle term is the $\frac{n + 1}{2}$ th term.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

$a = 6$ , $d = 7$ and the last term is 230. Using $230 = 6 + (n - 1) 7$ : $(n - 1) = 32$ , so $n = 33$ terms.
1 mark
With 33 terms (an odd number), the middle term is the $\frac{33 + 1}{2} = 17$ th term: $t_{17} = 6 + 16 (7) = 118$ .
1 mark

Answer: Middle term = 118

Where the marks are

Finds the number of terms n = 33 (1 mark)
Finds the middle term $t_{17} = 118$ (1 mark)

Revise the chapter

Chapter: Arithmetic Progressions (notes, formulas, where marks are lost and every past question)

Practise this chapterBoard-style questions from Arithmetic Progressions, one at a time, marked against the answer key and marking points.Back to the full paperSample paper 2025-26 (Standard): every question, by section.

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CBSE Class 10 Mathematics Standard sample paper 2025-26: question 21(B)

Hints

Step-by-step solution

Revise the chapter

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