CBSE Class 10 Mathematics Basic 2024: question 37
Set in the CBSE Class 10 board exam of 2024, paper 430/4/1, section E, question 37, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q37 · 4 marks · Case-basedCompetency-basedCoordinate Geometry
Case Study – 2
Resident Welfare Association (RWA) of Gulmohar Society in Delhi, have installed three electric poles A, B and C in the society's common park. Despite these three poles, some parts of the park are still in the dark. So, RWA decides to have one more electric pole D in the park. The park can be modelled as a coordinate system given below.
On the basis of the above information, answer the following questions :
- (i)1 mark
What is the position of the pole C ?
- (ii)1 mark
What is the distance of the pole B from the corner O of the park ?
- (iii)(a)2 marks
Find the position of the fourth pole D so that the four points A, B, C and D form a parallelogram ABCD.
OR
(iii)(b)2 marksFind the distance between poles A and C.
Figure in the paper: Coordinate graph with X-axis and Y-axis meeting at origin O, grid marked 1 to 6 on X and 1 to 10 on Y. Three poles drawn as dots with upward arrows: A at (2, 7) with its arrow going up to about 8; B at (6, 6) with arrow going up to about 7; C at (5, 4) with arrow going up to about 5. The park is the first-quadrant region shown. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 430/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Read the coordinates of each pole from the grid, x first and then y.
Hint 2
For distances, use ; for O, the coordinates are (0, 0).
Hint 3
In a parallelogram ABCD the diagonals AC and BD bisect each other, so their mid-points are the same.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) Reading from the graph, pole C is at the point (5, 4).
- ½ mark
(ii) Pole B is at (6, 6) and O is at (0, 0).
- ½ mark
By the distance formula, units.
- 1 mark
(iii)(a) The poles are at A(2, 7), B(6, 6) and C(5, 4). Let D be .
The diagonals of a parallelogram bisect each other, so the mid-point of AC equals the mid-point of BD:
- ½ mark
Comparing x-coordinates:
- ½ mark
Comparing y-coordinates:
So the fourth pole D is at (1, 5).
- 1½ marks
(iii)(b) The poles are at A(2, 7) and C(5, 4).
- ½ mark
units
Answer: (i) C(5, 4); (ii) units; (iii)(a) D(1, 5); (iii)(b) units
Where the marks are
- (i) Writes C as (5, 4) (1 mark)
- (ii) Takes B(6, 6) and applies the distance formula from O (½ mark)
- (ii) BO = (½ mark)
- (iii)(a) Equates the mid-points of the diagonals AC and BD (1 mark)
- (iii)(a) Finds x = 1 (½ mark)
- (iii)(a) Finds y = 5, so D(1, 5) (½ mark)
- (iii)(b) Substitutes correctly in the distance formula for AC (1½ marks)
- (iii)(b) AC = (½ mark)
Revise the chapter
- Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
- Topic: Distance Formula
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.