CBSE Class 10 Mathematics Basic 2024: question 28(b)
Set in the CBSE Class 10 board exam of 2024, paper 430/4/1, section C, question 28(b), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q28(b) · 3 marks · Short answerQuadratic Equations
Find the values of 'k' for which the quadratic equation has real and equal roots. Also, find the roots.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 430/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Real and equal roots means b² − 4ac = 0.
Hint 2
Factorise 4k² − 24k and reject the value that removes the x² term. Then substitute back and solve.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
For equal roots, . Here , so .
- 1 mark
or . Since makes the equation non-quadratic, .
- 1 mark
With : .
Answer: k = 6; roots are 1, 1
Where the marks are
- Sets D = 0 to get 4k² − 24k = 0 (1 mark)
- k = 6, rejecting k = 0 (1 mark)
- Finds the roots x = 1, 1 (1 mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
- Topic: Nature of Roots and Discriminant
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