MathsCBSE Class 10 · Basic · Board exam 2024, set 430/2/1 · 2 marks · Very short answer

CBSE Class 10 Mathematics Basic 2024: question 22(b)

Set in the CBSE Class 10 board exam of 2024, paper 430/2/1, section B, question 22(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q22(b) · 2 marks · Very short answerPair of Linear Equations in Two Variables

Solve for $x$ and $y$ :
$x - 3 y = 7$
$3 x - 3 y = 5$

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 430/2/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Look at the $y$ -terms in both equations. What do you notice?

Hint 2

The coefficients of $y$ are equal, so subtracting one equation from the other removes $y$ .

Hint 3

Put the value of $x$ back into either equation to get $y$ .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

Subtract $x - 3 y = 7$ from $3 x - 3 y = 5$ : $2 x = - 2 \Rightarrow x = - 1$
1 mark
Substitute in $x - 3 y = 7$ : $- 1 - 3 y = 7 \Rightarrow - 3 y = 8 \Rightarrow y = - \frac{8}{3}$
1 mark

Answer: $x = - 1$ , $y = - \frac{8}{3}$

Where the marks are

Eliminates $y$ and finds $x = - 1$ (1 mark)
Finds $y = - \frac{8}{3}$ (1 mark)

Revise the chapter

Chapter: Pair of Linear Equations in Two Variables (notes, formulas, where marks are lost and every past question)
Topic: Elimination Method

Practise this chapterBoard-style questions from Pair of Linear Equations in Two Variables, one at a time, marked against the answer key and marking points.Back to the full paper2024 board paper, set 430/2/1 (Basic): every question, by section.

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CBSE Class 10 Mathematics Basic 2024: question 22(b)

Hints

Step-by-step solution

Revise the chapter

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