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MathsCBSE Class 10 · Standard · Board exam 2024, set 30/5/1 · 5 marks · Long answer

CBSE Class 10 Mathematics Standard 2024: question 32(b)

Set in the CBSE Class 10 board exam of 2024, paper 30/5/1, section D, question 32(b), for 5 marks. Try it first; the hints and our step-by-step solution are below.

Q32(b) · 5 marks · Long answerQuadratic Equations

The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find their present ages.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/5/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Let the son's present age be x; write the man's age in terms of x.

Hint 2

Add 8 to both ages and translate '4 years more than three times' into an equation.

Hint 3

Solve the quadratic and discard any value that cannot be an age.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let the present age of the son be years. Then the present age of the man years.

    1 mark
  2. After 8 years: man's age , son's age . According to the question,

    1 mark
  3. 1 mark
  4. or

    1 mark
  5. Age cannot be negative, so ; hence .

    ½ mark
  6. Present age of son = 4 years; present age of man years. (Check: after 8 years, 40 = 3 × 12 + 4 ✓)

    ½ mark

Answer: Son: 4 years; Man: 32 years

Where the marks are

  • Takes son's age x and man's age (1 mark)
  • Forms equation (1 mark)
  • Gets (1 mark)
  • Factorises (1 mark)
  • Rejects negative root, x = 4 (½ mark)
  • States ages 4 years and 32 years (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.