CBSE Class 10 Mathematics Standard 2024: question 32(b)
Set in the CBSE Class 10 board exam of 2024, paper 30/5/1, section D, question 32(b), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q32(b) · 5 marks · Long answerQuadratic Equations
The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find their present ages.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Let the son's present age be x; write the man's age in terms of x.
Hint 2
Add 8 to both ages and translate '4 years more than three times' into an equation.
Hint 3
Solve the quadratic and discard any value that cannot be an age.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Let the present age of the son be years. Then the present age of the man years.
- 1 mark
After 8 years: man's age , son's age . According to the question,
- 1 mark
- 1 mark
or
- ½ mark
Age cannot be negative, so ; hence .
- ½ mark
Present age of son = 4 years; present age of man years. (Check: after 8 years, 40 = 3 × 12 + 4 ✓)
Answer: Son: 4 years; Man: 32 years
Where the marks are
- Takes son's age x and man's age (1 mark)
- Forms equation (1 mark)
- Gets (1 mark)
- Factorises (1 mark)
- Rejects negative root, x = 4 (½ mark)
- States ages 4 years and 32 years (½ mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
- Topic: Word Problems on Quadratic Equations
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