MathsCBSE Class 10 · Standard · Board exam 2024, set 30/1/1 · 1 mark · MCQ

CBSE Class 10 Mathematics Standard 2024: question 17

Set in the CBSE Class 10 board exam of 2024, paper 30/1/1, section A, question 17, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q17 · 1 mark · MCQCoordinate Geometry

The centre of a circle is at (2, 0). If one end of a diameter is at (6, 0), then the other end is at:

(A)(0, 0)
(B)(4, 0)
(C)(-2, 0)
(D)(-6, 0)

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

The centre bisects every diameter.

Hint 2

Apply the mid-point formula with the unknown end $(x, y)$ .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

The centre is the mid-point of the diameter. Let the other end be $(x, y)$ . Then $\frac{6 + x}{2} = 2$ and $\frac{0 + y}{2} = 0$ .
So $x = - 2$ and $y = 0$ , and the other end is $(- 2, 0)$ . The answer is option (C).
1 mark

Answer: (-2, 0), option (C)

Where the marks are

Uses the mid-point formula to get $(- 2, 0)$ , option (C) (1 mark)

Revise the chapter

Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
Topic: Midpoint Formula and Points of Trisection

Practise this chapterBoard-style questions from Coordinate Geometry, one at a time, marked against the answer key and marking points.Back to the full paper2024 board paper, set 30/1/1 (Standard): every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.

CBSE Class 10 Mathematics Standard 2024: question 17

Hints

Step-by-step solution

Revise the chapter

More questions from Coordinate Geometry