CBSE Class 10 Mathematics Standard sample paper 2024-25: question 15
From the official CBSE sample question paper for 2024-25, section A, question 15, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2024-25.
Hints
Open one hint at a time and try again before the next.
Hint 1
The shortest distance from a point to a line is along the perpendicular.
Hint 2
Keep the -coordinate the same and make .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
The point on the -axis nearest to a given point is the foot of the perpendicular from that point to the -axis.
- 1 mark
For the foot is , at distance . Any other point is at distance . The answer is option (B).
Answer: , option (B)
Where the marks are
- Uses the perpendicular to the -axis to get (1 mark)
Revise the chapter
- Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
- Topic: Distance Formula
More questions from Coordinate Geometry
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- Sample paper 2024-25 (Standard), Q25 · 2 marksShow that the points A(-5,6), B(3,0) and C(9,8) are the vertices of an isosceles triangle.
- 2024 board paper, set 30/1/1 (Standard), Q6 · 1 markAD is a median of Δ ABC with vertices A(5, -6), B(6, 4) and C(0, 0). Length AD is equal to:
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.