CBSE Class 10 Mathematics Basic sample paper 2024-25: question 30(A)
From the official CBSE sample question paper for 2024-25, section C, question 30(A), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q30(A) · 3 marks · Short answerCircles
In the given figure, PA and PB are tangents to a circle centred at O. Prove that (i) OP bisects (ii) OP is the right bisector of AB.
Figure in the paper: A circle with centre O. External point P with tangents PA and PB touching the circle at A and B. Chord AB is drawn, and the line OP meets AB at Q. Radii OA and OB are drawn. See it in the official paper.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2024-25.
Hints
Open one hint at a time and try again before the next.
Hint 1
Tangents drawn from an external point are equal, and radii are equal. Look for congruent triangles.
Hint 2
For (ii), compare triangles AQP and BQP. The two angles at Q form a linear pair.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) In and :
- [radii]
- [tangents from an external point are equal]
- [common]
So [SSS]. Hence [CPCT], i.e. OP bisects .
- 1 mark
(ii) In and :
- [equal tangents]
- [from (i)]
- [common]
So [SAS]. Hence and [CPCT].
- 1 mark
Since AQB is a straight line, , so .
Thus OP is perpendicular to AB and bisects it at Q, so OP is the right (perpendicular) bisector of AB.
Answer: OP bisects ∠APB, and OP is the perpendicular bisector of AB (proved).
Where the marks are
- , giving (1 mark)
- , giving and equal angles at Q (1 mark)
- Linear pair gives , so OP is the right bisector of AB (1 mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.