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MathsCBSE Class 10 · Basic · Board exam 2023, set 430/5/1 · 3 marks · Short answer

CBSE Class 10 Mathematics Basic 2023: question 26(b)

Set in the CBSE Class 10 board exam of 2023, paper 430/5/1, section C, question 26(b), for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q26(b) · 3 marks · Short answerCompetency-basedPair of Linear Equations in Two Variables

Five years ago, Amit was thrice as old as Baljeet. Ten years hence, Amit shall be twice as old as Baljeet. What are their present ages?

Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/5/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Let the present ages be x and y; five years ago they were x − 5 and y − 5.

Hint 2

Write one equation for 'five years ago' and one for 'ten years hence', then eliminate x.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let Amit's present age be years and Baljeet's be years. Five years ago: …(i)

    1 mark
  2. Ten years hence: …(ii)

    1 mark
  3. (ii) − (i): ; then . Amit is 50 years and Baljeet is 20 years old.

    1 mark

Answer: Amit = 50 years, Baljeet = 20 years

Where the marks are

  • Forms (1 mark)
  • Forms (1 mark)
  • Solves to get , (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.