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MathsCBSE Class 10 · Basic · Board exam 2023, set 430/5/1 · 2 marks · Very short answer

CBSE Class 10 Mathematics Basic 2023: question 24(b)

Set in the CBSE Class 10 board exam of 2023, paper 430/5/1, section B, question 24(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q24(b) · 2 marks · Very short answerCoordinate Geometry

Show that the points A(3, 0), B(6, 4) and C(-1, 3) are vertices of a right-angled triangle.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/5/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Use the distance formula to find the squares of all three sides.

Hint 2

Check whether the largest square equals the sum of the other two (converse of Pythagoras).

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. ½ mark
  2. ½ mark
  3. ½ mark
  4. , so by the converse of Pythagoras theorem is right-angled at A.

    ½ mark

Answer: , so ABC is right-angled at A.

Where the marks are

  • (½ mark)
  • (½ mark)
  • (½ mark)
  • Shows and concludes right angle (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.