CBSE Class 10 Mathematics Basic 2023: question 24(b)
Set in the CBSE Class 10 board exam of 2023, paper 430/5/1, section B, question 24(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q24(b) · 2 marks · Very short answerCoordinate Geometry
Show that the points A(3, 0), B(6, 4) and C(-1, 3) are vertices of a right-angled triangle.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Use the distance formula to find the squares of all three sides.
Hint 2
Check whether the largest square equals the sum of the other two (converse of Pythagoras).
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
- ½ mark
- ½ mark
- ½ mark
, so by the converse of Pythagoras theorem is right-angled at A.
Answer: , so ABC is right-angled at A.
Where the marks are
- (½ mark)
- (½ mark)
- (½ mark)
- Shows and concludes right angle (½ mark)
Revise the chapter
- Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.