CBSE Class 10 Mathematics Basic 2023: question 32(A)
Set in the CBSE Class 10 board exam of 2023, paper 430/4/1, section D, question 32(A), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q32(A) · 5 marks · Long answerSome Applications of Trigonometry
The shadow of a tower standing on a level ground is found to be m longer when the Sun's altitude is than when it was . Find the height of the tower.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Draw the tower and two shadows: the shadow at 30° is 40 m longer than the shadow at 60°.
Hint 2
Write tan 60° and tan 30° in the two right triangles and eliminate x.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Figure: tower AB = m with foot A; C and D on the ground on the same side, m (shadow at ), m, , .
- 1½ marks
In right : ...(1)
- 1½ marks
In right : ...(2)
- ½ mark
Substituting (1) in (2): m
- ½ mark
m. Height of the tower is m (≈ 34.64 m).
Answer: Height of tower = 20√3 m (≈ 34.64 m)
Where the marks are
- Correct figure (1 mark)
- giving (1½ marks)
- giving (1½ marks)
- Finds m (½ mark)
- Height m (½ mark)
Revise the chapter
- Chapter: Some Applications of Trigonometry (notes, formulas, where marks are lost and every past question)
- Topic: Problems with Two Right Triangles
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