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MathsCBSE Class 10 · Basic · Board exam 2023, set 430/2/1 · 4 marks · Case-based

CBSE Class 10 Mathematics Basic 2023: question 38

Set in the CBSE Class 10 board exam of 2023, paper 430/2/1, section E, question 38, for 4 marks. Try it first; the hints and our step-by-step solution are below.

Q38 · 4 marks · Case-basedCompetency-basedSurface Areas and Volumes

Case Study 3. A wooden toy is shown in the picture. This is a cuboidal wooden block of dimensions . On its top there are seven cylindrical hollows for bees to fit in. Each cylindrical hollow is of height 3 cm and radius 2 cm.

Based on the above, answer the following questions:

  1. (i)

    Find the volume of wood carved out to make one cylindrical hollow.

    1 mark
  2. (ii)

    Find the lateral surface area of the cuboid to paint it with green colour.

    1 mark
  3. (iii)

    (a) Find the volume of wood in the remaining cuboid after carving out seven cylindrical hollows.

    2 marks
  4. OR

    (iii)

    (b) Find the surface area of the top surface of the cuboid to be painted yellow.

    2 marks

Figure in the paper: Photograph of a yellow cuboidal wooden toy with a honeycomb pattern on its front face. Seven circular hollows are arranged in a honeycomb pattern on the top face, each hollow is coloured-outlined, and colourful bee-shaped rods/pegs stand below the block. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/2/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Each hollow is a cylinder: use .

Hint 2

Lateral surface area of a cuboid is , taking the 4 cm side as height.

Hint 3

For the top surface, remove the areas of the seven circular openings from the rectangle's area.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (i) Volume of one hollow cm³ cm³.

    1 mark
  2. (ii) Lateral surface area of cuboid cm².

    1 mark
  3. (iii)(a) Volume of 7 hollows cm³.

    ½ mark
  4. Volume of the full cuboid cm³.

    1 mark
  5. Remaining wood cm³.

    ½ mark
  6. (iii)(b) Top area to be painted = area of top face − area of 7 circular openings

    1 mark
  7. cm².

    1 mark

Answer: (i) 264/7 cm³ ≈ 37.71 cm³; (ii) 248 cm²; (iii)(a) 688 cm³; (iii)(b) 150 cm²

Where the marks are

  • Volume of one cylindrical hollow = 264/7 cm³ (1 mark)
  • LSA = 2(14×4 + 17×4) = 248 cm² (1 mark)
  • (iii)(a) Volume of 7 hollows 264 cm³ (½ mark), cuboid volume 952 cm³ (1 mark), remaining 688 cm³ (½ mark)
  • (iii)(b) Expression 14×17 − 7πr² with values (1 mark), answer 150 cm² (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.