CBSE Class 10 Mathematics Basic 2023: question 15
Set in the CBSE Class 10 board exam of 2023, paper 430/1/1, section A, question 15, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q15 · 1 mark · MCQTriangles
In the above figure, the criterion of similarity by which is :
- (A)SSA (Side – Side – Angle) Similarity
- (B)ASA (Angle – Side – Angle) Similarity
- (C)SAS (Side – Angle – Side) Similarity
- (D)AA (Angle – Angle) Similarity
Figure in the paper: Triangle ABC with BC = 3.5 cm, AB = 2.2 cm and angle B = 50°. Triangle PQR with QR = 7 cm, PQ = 4.4 cm and angle Q = 50°. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Compare the ratios of the given sides.
Hint 2
Is the 50° angle between those sides?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
, , and included .
- 1 mark
Two sides proportional with included angle equal ⇒ SAS similarity. Option (C).
Answer: SAS similarity, option (C)
Where the marks are
- Shows sides proportional with equal included angle, SAS (1 mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
More questions from Triangles
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- 2025 board paper, set 30/1/1 (Standard), Q24(b) · 2 marksIn the given figure, QR/QS = QT/PR and ∠ 1 = ∠ 2, show that △ PQS ~ △ TQR.
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.