CBSE Class 10 Mathematics Standard 2023: question 21(b)
Set in the CBSE Class 10 board exam of 2023, paper 30/5/1, section B, question 21(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q21(b) · 2 marks · Very short answerCoordinate Geometry
Point P(x, y) is equidistant from points A(5, 1) and B(1, 5). Prove that .
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 30/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
'Equidistant' means PA = PB.
Hint 2
Square both distances to avoid square roots, then expand and cancel the and terms.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
P is equidistant from A and B, so , i.e. . By the distance formula:
. - 1 mark
Expanding:
. Hence proved.
Answer: PA² = PB² simplifies to x = y (proved).
Where the marks are
- Writes PA² = PB² using the distance formula (1 mark)
- Simplifies correctly to x = y (1 mark)
Revise the chapter
- Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
- Topic: Distance Formula
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