CBSE Class 10 Mathematics Standard 2023: question 12
Set in the CBSE Class 10 board exam of 2023, paper 30/4/1, section A, question 12, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q12 · 1 mark · MCQTriangles
In the given figure, . If AC = 6 cm, BC = 5 cm, QR = 3 cm and PR = x; then the value of x is:
- (A)3.6 cm
- (B)2.5 cm
- (C)10 cm
- (D)3.2 cm
Figure in the paper: Two triangles side by side. Triangle ABC: vertices A (top left), C (top right), B (bottom). AC = 6 cm (top side), BC = 5 cm (slanted side). Triangle QPR: vertices R (top), Q (bottom left), P (bottom right). QR = 3 cm (left slanted side), PR = x (right slanted side). Base QP is horizontal. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 30/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Match the vertices in the order they are written in the similarity statement.
Hint 2
AC corresponds to QR and BC corresponds to PR. Set up the ratio.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
From the vertices correspond as , , . So and .
.
- 1 mark
cm. So the answer is option (B).
Answer: 2.5 cm, option (B)
Where the marks are
- Chooses option (B) 2.5 cm (1 mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
- Topic: Problems on Similar Triangles
More questions from Triangles
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.