CBSE Class 10 Mathematics Standard sample paper 2023-24: question 23
From the official CBSE sample question paper for 2023-24, section B, question 23, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q23 · 2 marks · Very short answerCircles
From an external point P, two tangents, PA and PB are drawn to a circle with centre O. At a point E on the circle, a tangent is drawn to intersect PA and PB at C and D, respectively. If PA = 10 cm, find the perimeter of PCD.
Figure in the paper: Circle with centre O. External point P with tangents PA (touching at A, upper) and PB (touching at B, lower). A third tangent touches the circle at E, meeting PA at C and PB at D; the triangle PCD is formed. See it in the official paper.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2023-24.
Hints
Open one hint at a time and try again before the next.
Hint 1
Tangents drawn from the same external point are equal.
Hint 2
Split CD into CE + ED and replace each part by an equal tangent.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
, and [tangents from an external point are equal].
- 1 mark
Perimeter of . Replacing CE by CA and ED by DB gives .
- ½ mark
Perimeter cm.
Answer: 20 cm
Where the marks are
- States the equal-tangent pairs (½ mark)
- Rewrites the perimeter as PA + PB (1 mark)
- Gets 20 cm (½ mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
More questions from Circles
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- 2023 board paper, set 30/1/1 (Standard), Q5 · 1 markIn the given figure, PQ is tangent to the circle centred at O. If ∠ AOB = 95°, then the measure of ∠ ABQ will …
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.